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7a^2-5a-8=0
a = 7; b = -5; c = -8;
Δ = b2-4ac
Δ = -52-4·7·(-8)
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{249}}{2*7}=\frac{5-\sqrt{249}}{14} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{249}}{2*7}=\frac{5+\sqrt{249}}{14} $
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